Question

Ayúdenme a resolver.
Porfa ​

Answer 1

Respuesta:

1)$x^{2}$+3x+1

2)$\frac{4x+6}{x}$

Explicación paso a paso:

1) 5*x+(x-1)(x-1)

=>5x+$x^{2}$-2x+1

=>$x^{2}$+3x+1

2) $\frac{7x+3}{x^2}+\frac{4x-1}{x}-\frac{3}{x^2}$

=>$\frac{7}{x}+\frac{4x-1}{x}$

=>$\frac{7+4x-1}{x}$

=>$\frac{4x+6}{x}$