Question

Ayúdenme a resolver por favor f(x)= (3x²+4) ² (4 x=-8)²

Answer 1

f(x) = (3x²+4) ² (4x -8)²

0 = [(3x² + 4) (4x - 8)]²

0 = (12x³ - 24x² + 16x - 32)²

12x² • (x - 2) + 16 (x - 2) = 0

4 (x-2) (3x² + 4) = 0

(x - 2) (3x² + 4) = 0

x - 2 = 0

3x² + 4 = 0

x = 2

x e̷ ℝ

X = 2

Answer 2

$f(x) = ( {3x}^{2} + 4 {)}^{2} (4 x - 8 {)}^{2} \\ 0 = ((3 {x}^{2} + 4)(4x - 8) {)}^{2} \\ 0 = (12 {x}^{3} - 24 {x}^{2} + 16x - 32 {)}^{2} \\ (12 {x}^{3} - 24 {x}^{2} + 16x - 32 {)}^{2} = 0 \\ 12 {x}^{2} (x - 2) + 16(x - 2) = 0 \\ 4(x - 2)(3 {x}^{2} + 4) = 0 \\ (x - 2)(3 {x}^{2} + 4) = 0 \\ x - 2 = 0 \\ 3 {x}^{2} + 4 = 0 \\ \\ \bf \: x = 2 \\ \bf \: x = ∅$

х=2