Question

Ayúdenme a resolver las ecuaciones de primer grado siguientes por favor:
$.6x - 4 = 4x \times 8 \\ .3x - 5 = x + 13 \\ .2x - 5 = x + 4 - 2x \\ . - 3y + 2 = 5y + 8 - 2y \\ .2(x + 1) - 3(x - 2) = 5(x + 4) \\ .3(z - 1) + 5(z + 3) = - 6(z - 5) \\ .(4x + 5)(2x - 3) = 5$

Answer 1

6x-4=4x x 8
6x-4=32x
6x=32x+4
6x-32x=4
-26x=4
x= -2/13


3x-x-5=13
3x-x=13+5
2x=13+5
2x=18
x=18/2
x=9


2x-5=x+4-2x
2x-5= -x+4
2x+x-5=4
2x+x=4+5
3x=9
x=3


-3y+2=5y+8 -2y
-3y-2=3y+8
-3y-3y+2=8
-3y-3y=8-2
-6y=8-2
-6y=6
y= -1


2(x+1)-3(x-2)=5(x+4)
2x+2-3(x-2)=5(x+4)
2x+2-3x+6=5(x+4)
2x+2-3x+6=5x+20
-x+2+6=5x+20
-x+8=5x+20
-x-5x+8=20
-x-5x=20-8
-6x=20-8
-6x=12
x= -2


3(z-1)+5(z+3)= -6(z-5)
3z-3+5(z+3)=-6(z-5)
3z-3+5z+15=-6(z-5)
3z-3+5z+15=-6z+30
8z+12=-6z+30
8z+6z+12=30
8z+6z=30-12
14z=30-12
14z=18
z=9/7