Question

ayúdenme a resolver!!!

(4x)(4x)=

4x+4x+4x+4x=

(4m)(3m+2n)=

4m+4m+(3m+2n)+(3m+2n)=

(5a)(5a)=

5a+5a+5a+5a=

(3x)(2x+3y)=

3x+3x+(2x+3y)+(2x+3y)


ayuda ​

Answer 1

Explicación paso a paso:

(4x)(4x)=16x²

4x+4x+4x+4x= 16x

(4m)(3m+2n)= 12m²+8mn

4m+4m+(3m+2n)+(3m+2n)= 4m+4m+3m+2n+3m+2n= 8m+6m+4n= 14m+4n

(5a)(5a)= 25a²

5a+5a+5a+5a= 20a

(3x)(2x+3y)= 6x²+9xy

3x+3x+(2x+3y)+(2x+3y)= 6x+4x+6y= 10x+6y