Question

ayudenme a resolver [(3/4-1/2)/4/3+1]/(-3/4+1/3).3/2

Answer 1

Primero resuelve los parentesis

=> [(3/4-1/2)÷4/3+1]÷(-3/4+1/3)*3/2
=> (3/4-1/2)--> (1/4)
=> 4/3+1/1-->7/3
=>[1/4÷7/3] : (-3/4+1/3)*3/2
=> 1/4÷7/3-->  3/28

=> (-3/4+1/3)--> -5/12
=> -5/12*3/2--> -15/24--> Simplificas por 3--> -5/8

=> 3/28:-5/8--> 24/-140--> Simplificas por 2--> 12/-70--> 6/-35
=> 6/-35