Question

Ayúdenme a contestar esos dos problemas por favor , le doy corona al que me ayude:(

Answer 1

Respuesta:

$\cos(33) = \frac{PQ}{RQ} \\ \cos(33 ) = \frac{PQ}{25} \\ PQ = 25 \times \cos(33) \\ PQ= 21cm$

${PM}^{2} = {KM}^{2} - {KP}^{2} \\ {PM}^{2} = {10}^{2} - {7}^{2} \\ {PM}^{2} = 100 - 49 \\ {PM}^{2} = 51 \\ PM = \sqrt{51} \\ PM = 7.14mi$