Question

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(a+b)²=8
a²+b²=12​

Answer 1

Respuesta:

(a+b)²=8

$a + b = 2 \sqrt{2}$

$a + b = - 8 \sqrt{2}$

$a + b - b2 = \sqrt{2 - b}$

$a + b - b = - 2 \sqrt{2} - b$

$a = 2 \sqrt{2} - b$

$a = - 2 \sqrt{2 - b}$

$a = - b + 2 \sqrt{2}$

$a = - b2 - 2\sqrt{2}$

R/

$a = - b + 2 \sqrt{2}$

$a = - b - 2 \sqrt{2}$

2. a²+b²=12

a² = 12 - b

a = √12 - b²

a = -√12 - b²