Question

AYUDEN PE DOY CORONA

al menos 1 problema :v

Answer 1

Explicación paso a paso:

TE AYUDO "PE"

1)

$\frac{ {2}^{3} {2}^{4} {2}^{5} }{ {2}^{12} }$

$\frac{ {2}^{3 + 4 + 5} }{ {2}^{12} }$

$\frac{ {2}^{12} }{ {2}^{12} }$

1

2)

$\frac{ {3}^{6} }{ {3}^{7} } + \frac{5}{3}$

$\frac{1}{3} + \frac{5}{3}$

$\frac{6}{3}$

2

3)

FACTORIZE

$( {2}^{3} + {2}^{2} + 2 + 1) \times {2}^{x - 3} = 30$

$(8 + 4 + 3) \times {2}^{x - 3} = 30$

$15 \times {2}^{x - 3} = 30$

${2}^{x - 3} = 2$

$x - 3 = 1$

x=4

REEMPLAZO

(5x+2)²

(5(4)+2)²

(20+2)²

(22)²=484