Question

ayuden me a resolver el logaritmo de log( 2x)=log 32-log x

Answer 1

${log(2x)=log(32)-log(x)} \\{log(2x)=log( \frac{32}{x})}\\{2x= \frac{32}{x}}\\{x(2x)=32}\\{2x^2=32}\\{x^2= \frac{32}{2}}\\{x^2=16}\\{x= \sqrt{16} }\\{x=4}\\\\{salu2. :)$