Question

ayúdame porfa es para ahorita​

Answer 1

Respuesta:

f) $\sqrt{25}$ + (5)³= 5 + 125 = 130

g) $3^{6} /3^{4}$ - $\sqrt{49}$ - $7^{0}$ = 3² - 7 - 1 = 9 - 7 - 1 = 1

h) 8².$8^{0}$ - $\sqrt{100} - \sqrt{64}$ = 64 - 10 -8 = 46

i)$\sqrt{81}+2^{6}-(2^{2})^{3}$ = 9 + $2^{6}-2^{6}$ = 9

j)$12^{8}/12^{7}+16^{3}/8^{3}+\sqrt{121}$ = 12 + $(2^{4})^{3}/(2^{3})^{3}$ + 11 = 12 + $2^{3}$ + 11 = 12 + 8 + 11 = 31