Question

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Answer 1

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$\sqrt{45} - \sqrt{27 } - \sqrt{20}$

Simplificamos cada raíz individualmente.

$\sqrt{45} = \sqrt{9 \times 5} = \sqrt{ {3}^{2} \times 5} = \sqrt{ {3}^{2} } \sqrt{5} = 3 \sqrt{5}$

$\sqrt{27} = \sqrt{ {3}^{3} } = \sqrt{ {3}^{2 + 1} } = \sqrt{ {3}^{2} \times {3}^{1} } = \sqrt{ {3}^{2} \times 3} = \sqrt{ {3}^{2} } \sqrt{3 } = 3 \sqrt{3}$

$\sqrt{20} = \sqrt{4 \times 5} = \sqrt{ {2}^{2} \times 5} = \sqrt{ {2}^{2} } \sqrt{5} = 2 \sqrt{5}$

Agrupamos y calculamos los semejantes.

$3 \sqrt{5} - 2 \sqrt{5} = (3 - 2) \sqrt{5} = 1 \sqrt{5} = \sqrt{5}$

$\sqrt{5} - 3 \sqrt{3}$

Salu2!!