Question

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Answer 1

Respuesta:

$[E]=ML^{2} T^{ - 2}$

[E]=ML^{2} T^{ - 2}

Explicación paso a paso:

$[A]=L^{2} \\ [F]=MLT^{ - 2} \\ \\ del \: problema: R²+A \\ Entonces: \\ [R²]=[A] \\ [R²]=L² \\ [R]=L \\ \\ del \: problema: E=FR + ... \\ [E]=[FR] \\ [E]=[F][R] \\ [E]=MLT^{ - 2} . L \\ [E]=ML^{2} T^{ - 2}$