Question

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Answer 1

Respuesta:

Explicación:

Solución:

$V_{f} =V_{i} +at$

$V_{f} -V_{i} = at , entonces: \frac{V_{f} -V_{I} }{a} = t$

$Luego: t = \frac{V_{f} -V_{i} }{a}$

RESPUESTA:

$t = \frac{V_{f} -V_{i} }{a}$

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$\frac{1}{F} = \frac{1}{A} + \frac{1}{C}$

$\frac{1}{F} -\frac{1}{C} = \frac{1}{A} , entonces: A (\frac{C-F}{CF} )= 1$

$Luego: A = \frac{CF}{C-F}$

RESPUESTA:

$A = \frac{CF}{C-F}$

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$T = 2\pi \sqrt{\frac{L}{g} }$

$\frac{T}{2\pi } =\sqrt{\frac{L}{g} } , entonces: (\frac{T}{2\pi } )^{2} = (\sqrt{\frac{L}{g} })^{2}$

$\frac{T^{2} }{4\pi ^{2} } = \frac{L}{g} , entonces: (4\pi ^{2} )(L) = (T^{2} )(g)$

$Luego:$ $L = \frac{T^{2}g }{4\pi ^{2} }$

RESPUESTA:

$L = (\frac{T}{2\pi } )^{2} *g$

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$(T_{f} -T_{i} ) xc = L_{f} - L_{i}$   $,entonces: x= \frac{L_{f}-L_{I} }{C(T_{f} -T_{i} )}$

RESPUESTA:

$x = \frac{L_{f} -L_{i} }{C (T_{f} -T_{i}) }$