Question

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Answer 1

Respuesta:

la expresión traducida a lenguaje álgebraico es:

3X-5=20

Answer 2

$a)( {x}^{2} - 4x + 5 ) + (6 {x}^{2} + 3x - 6) = \\ {x}^{2} - 4x + 5 + 6 {x}^{2} + 3x - 6 = \\ ( {x}^{2} + 6 {x}^{2} ) + ( - 4x + 3x) + (5 - 6) = \\ 7 {x}^{2} + ( - x) + ( - 1) = \\ 7 {x}^{2} - x - 1$

$b)(13 {x}^{2} - 4x + 8) - (6 {x}^{2} - 3x - 6) = \\ 13 {x}^{2} - 4x + 8 - 6 {x}^{2} + 3x + 6 = \\ (13 {x}^{2} - 6 {x}^{2} ) + ( - 4x + 3x) + (8 + 6) = \\ 7 {x}^{2} + ( - x) + 14 = \\ 7 {x}^{2} - x + 14$

$c) {x}^{2} (4x - 3 {x}^{2} + 6) = \\ {x}^{2} \times 4x - {x}^{2} \times 3 {x}^{2} + {x}^{2} \times 6 = \\ 4 {x}^{3} - 3 {x}^{4} + 6 {x}^{2}$

$d)(14x - 49 {x}^{2} - 2 {x}^{3} ) \div 7x = \\ 14x \div 7x - 49 {x}^{2} \div 7x - 2 {x}^{3} \div 7x = \\ 2 - 7x - \frac{2}{7} {x}^{2}$

$e)x( {x}^{2} - 3x ) - (5 {x}^{3} - {x}^{2} ) = \\ ( {x}^{3} - 3 {x}^{2} ) - (5 {x}^{3} - {x}^{2} ) = \\ {x}^{3} - 3 {x}^{2} - 5 {x}^{3} + {x}^{2} = \\ ( {x}^{3} - 5 {x}^{3} ) + ( - 3 {x}^{2} + {x}^{2} ) = \\ - 4 {x}^{3} + ( - 2 {x}^{2} ) = \\ - 4 {x}^{3} - 2 {x}^{2}$