Question

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Answer 1

Explicación paso a paso:

${n}^{2} + {3}^{2} = { \sqrt{10} }^{2}$

${n}^{2} + 9 = 10$

${n}^{2} = 10 - 9$

${n}^{2} = 1$

$n = \sqrt{1}$

$n = 1$

ENTONCES:

$\tan( \alpha ) = \frac{n}{3}$

$\tan( \alpha ) = \frac{1}{3}$