Matemáticas, pregunta formulada por Mrmandibula, hace 7 meses

AYUDAAAAAAAAAAAAAAA:c​

Adjuntos:

Respuestas a la pregunta

Contestado por Grendyqwq
0

Explicación paso a paso:

a) -4.(2x-1) +18 = 6 -2 (-5+x)

-8x+ 4 +18 = 6 +10 -2x

-8x +22 = 16 - 2x

-8x +2x = 16 -22

-6x = -6

x = 1

b) 4 .(x-1) +10 = 2(x+7)

4x -4 +10 = 2x + 14

4x + 6 = 2x +14

4x -2x = 14 - 6

2x = 8

x= 4

c)

2 {}^{3}  =  -  \frac{1}{4} x {}^{2}  + 5 \times 2 {}^{2}  \\ 8 =  -  \frac{1}{4} x {}^{2}  + 5 \times 4 \\ 8 =  -  \frac{1}{4} x {}^{2}  + 20 \\ 32 =  - x {}^{2}  + 80 \\ x {}^{2}  = 48 \\ x = 4 \sqrt{3}

espero te halla ayudado <3

Contestado por TheMexicanTacosG
1

a)  -4 × (2x - 1) + 18 = 6 - 2×(-5+x) \\

  •  -8x + 4 + 18 = 6 + 10 - 2x \\

  •  4 + 18 = 6 + 10 - 2x + 8x \\

  •  22 - 16 = 6x \\

  •  8 = 6x \\

  •  \frac{8}{6} = x \\

  •  \boxed{\frac{4}{3} = x }\\

b)  4×(x-1) + 10 = 2×(x+7) \\

  •  4x - 4 + 10 = 2x + 14 \\

  •  4x - 2x = 14 - 6 \\

  •  2x = 8 \\

  •  x = \frac{8}{2}\\

  •  \boxed{x = 4} \\

c)  \frac{{2}^{13}}{{2}^{10}} = \frac{{x}^{2}}{-4} + 5×{(-2)}^{2} \\

  •  {2}^{13-10} = \frac{ {x}^{2}}{-4} + 5×4 \\

  •  {2}^{3} = \frac{{x}^{2}}{-4} + 20 \\

  •  (-4)×8 = {x}^{2} + (-4)(20) \\

  •  -32 = {x}^{2} - 80 \\

  •  80 - 32 = {x}^{2} \\

  •  48 = {x}^{2} \\

  •  \boxed{\sqrt{48} = x} \\
Otras preguntas