Question

Ayudaaaaaaaaa, le pongo Corona quien lo resuelva ​

Answer 1

Respuesta:

1) $9a^{4} -36a^{2}x^{3}+36x^{6}$

2) $16a^{4} -56a^{2}x^{3}+49x^{6}$

3) $25a^{4} -90a^{2}x^{3}+81x^{6}$

4) $36a^{4}-108a^{2}x^{3}+81x^{6}$

5) $64a^{4}-160a^{2}x^{3}+100x^{6}$

Explicación paso a paso:

1)

$(3a^{2} -6x^{3})^{2} = (3a^{2} )^{2} -2(3a^{2})(6x^{3})+(6x^{3})^{2}=9a^{4} -36a^{2}x^{3}+36x^{6}$

2)

$(4a^{2}-7x^{3} )^{2} =(4a^{2})^{2}-2(4a^{2})(7x^{3})+(7x^{3})^{2} =16a^{4} -56a^{2}x^{3}+49x^{6}$

3)

$(5a^{2}-9x^{3})^{2}=(5a^{2})^{2}-2(5a^{2})(9x^{3}) +(9x^{3})^{2}=25a^{4} -90a^{2}x^{3}+81x^{6}$

4)

$(6a^{2}-9x^{3})^{2}=(6a^{2})^{2}-2(6a^{2})(9x^{3})+(9x^{3})^{2}=36a^{4}-108a^{2}x^{3}+81x^{6}$

5)

$(8a^{2}-10x^{3})^{2}=(8a^{2})^{2}-2(8a^{2})(10x^{3})+(10x^{3})^{2}=64a^{4}-160a^{2}x^{3}+100x^{6}$