Question

ayudaaaaaa porfavor ​

Answer 1

$f = \frac{ \sqrt[200] {6}^{400} + \sqrt[100] {4}^{200} }{ \sqrt[199] {2}^{398} } \\ f = \frac{ {6}^{2} + {4}^{2} }{ {2}^{2} } \\ f = \frac{36 + {2}^{4} }{4 } \\ f = \frac{36 + 16}{4} \\ f = \frac{52}{4} \\ f = 13$