Question

ayudaaaaaa, me urge, porfis
4x²+8x-4

3x²+6x-2

Answer 1

Explicación paso a paso:

Aplica formula general para encontrar las dos raíces

$x = \frac{ - b \:± \sqrt{ {b}^{2} - 4ac} }{2a}$

A) 4x²+8x-4

a=4,b= 8,c=-4

$x1 = \frac{ - 8± \sqrt{ {8}^{2} - 4(4)( - 4)} }{2(4)} = \frac{ - 8 ± \sqrt{64 + 64} }{8} = \frac{ - 8 + 11.31}{8} = \frac{3.31}{8} = 0.41$

$x2 = \frac{ - 8 - 11.31}{8} = - \frac{19}{8} = - 2.37$

B) a=3, b=6, c=-2

$x1 = \frac{ - 6± \sqrt{ {6}^{2} - 4(3)( - 2) } }{2(3)} = \frac{ - 6± \sqrt{36 + 24} }{6} = \frac{ - 6 + \sqrt{60} }{6} = \frac{ - 6 + 7.7}{6} = \frac{1.74}{6} =0.29$

$x2 = \frac{ - 6 - 7.7}{6} = \frac{ - 13.7}{6} = - 2.28$