Matemáticas, pregunta formulada por amym4247, hace 1 mes

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Contestado por murdock14
1

(3)

\\ \pink{{\hspace{0 pt}\above 2.2pt}\boldsymbol{\mathsf{ \frac{14}{4}x -  \frac{11}{4} =  \frac{3}{4}x +  \frac{10}{4}   }}{\hspace{0pt}\above 2.2pt}}

\\ \pink{{\hspace{0 pt}\above 2.2pt}\boldsymbol{\mathsf{ \frac{5}{2}x -\frac{11}{4} =  \frac{3}{4}x +  \frac{10}{4} }}{\hspace{0pt}\above 2.2pt}}

 \\ \pink{{\hspace{0 pt}\above 2.2pt}\boldsymbol{\mathsf{10x - 11 = 3x + 10}}{\hspace{0pt}\above 2.2pt}}

 \\ \pink{{\hspace{0 pt}\above 2.2pt}\boldsymbol{\mathsf{10x - 3x = 10 + 11}}{\hspace{0pt}\above 2.2pt}}

 \\ \pink{{\hspace{0 pt}\above 2.2pt}\boldsymbol{\mathsf{7x = 21}}{\hspace{0pt}\above 2.2pt}}

 \\ \pink{{\hspace{0 pt}\above 2.2pt}\boldsymbol{\mathsf{x = 3}}{\hspace{0pt}\above 2.2pt}}

(4)

 \\ \pink{{\hspace{0 pt}\above 2.2pt}\boldsymbol{\mathsf{ \frac{3}{4} x -  \frac{2}{3} =  \frac{1}{3}x +  \frac{2}{5} }}{\hspace{0pt}\above 2.2pt}}

 \\ \pink{{\hspace{0 pt}\above 2.2pt}\boldsymbol{\mathsf{45x - 40 = 20x + 24}}{\hspace{0pt}\above 2.2pt}}

 \\ \pink{{\hspace{0 pt}\above 2.2pt}\boldsymbol{\mathsf{45x - 20x = 24 + 40}}{\hspace{0pt}\above 2.2pt}}

 \\ \pink{{\hspace{0 pt}\above 2.2pt}\boldsymbol{\mathsf{25x = 64}}{\hspace{0pt}\above 2.2pt}}

 \\ \pink{{\hspace{0 pt}\above 2.2pt}\boldsymbol{\mathsf{x =  \frac{64}{25} }}{\hspace{0pt}\above 2.2pt}}

 \\ \green{{\hspace{0 pt}\above 2.2pt}\boldsymbol{\mathsf{✓}}{\hspace{0pt}\above 2.2pt}}

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