Question

Ayudaaaa es para hoy

Answer 1

Al realizar las operaciones de matrices se obtiene:

$\left[\begin{array}{cccc}4&3&5&42\\0&-7&3&-6\\0&23&2&10\end{array}\right]$

Dada la siguiente matriz; operaciones algebraicas entre filas.

$\left[\begin{array}{cccc}4&3&5&42\\3&4&3&33\\2&5&2&29\end{array}\right]$

F₃ ⇒ F₁ - 2F₃

= [4 - 2(2)]; [3 - 2(5)];  [5 - 2(2)]; [42 - 2(29)]

= 0; -30; 1; -16

sustituir;

$\left[\begin{array}{cccc}4&3&5&42\\3&4&3&33\\0&-30&1&-16\end{array}\right]$

F₂ ⇒ 3F₁ - 4F₂

= [3(4)- 4(3)]; [3(3)-4(4)]; [3(5)-4(3)]; [3(42)-4(33)]

= 0; -7; 3; -6

sustituir;

$\left[\begin{array}{cccc}4&3&5&42\\0&-7&3&-6\\0&-30&1&-16\end{array}\right]$

F₃ ⇒ F₂ - F₃

= [0-0]; [-7+30]; [3-1]; [-6+16]

= 0; 23; 2; 10

sustituir;

$\left[\begin{array}{cccc}4&3&5&42\\0&-7&3&-6\\0&23&2&10\end{array}\right]$