Question

ayudaaa por favor 8x mas 5y =33 menos 2x menos 4y =menos44

Answer 1

$\left \{ {{8x+5y=33} \atop {2x-4y=44}} \right.$

= x=33-5y/8

  x=44+4y/2

= $\frac{33-5y}{8}=\frac{44+4y}{2}$

= 66-10y= 352+32y

=  -42y=286

entonces

y= 143/21

X= 748/21