Matemáticas, pregunta formulada por seventen21, hace 16 horas

Ayudaaa es importante doy corona
1 (-1/9) (-2ax⁴y) (5x²) (-1/2xy)=
2 (2ab³)(-1/3a³bcy)(3/2ab²x)(-5/3axy)=
3 (4m²b³)(-1/5mb²q²)(-3/5mb²q³x)(1/3mg²x²)=
4 (2a²-1/3ab+b²) (-3a)=
5 (1/2x³-2x³y+xy²+y³) (1/4xy)=
6 (0,2m³-m²+1/5m) (-2m³n)=
7 (-11/5abx³)(-5a³b+2/9ab³-5)=
8 (16/5ab²c³) (-2ab+bc-1/9a²c)=

Respuestas a la pregunta

Contestado por ramirojosecorona
0

Respuesta:

1 (-1/9) (-2ax⁴y) (5x²) (-1/2xy)=

2 (2ab³)(-1/3a³bcy)(3/2ab²x)(-5/3axy)=

3 (4m²b³)(-1/5mb²q²)(-3/5mb²q³x)(1/3mg²x²)=

4 (2a²-1/3ab+b²) (-3a)=

5 (1/2x³-2x³y+xy²+y³) (1/4xy)=

6 (0,2m³-m²+1/5m) (-2m³n)=

7 (-11/5abx³)(-5a³b+2/9ab³-5)=

8 (16/5ab²c³) (-2ab+bc-1/9a²c)=

Explicación paso a paso:


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