Question

AYUDAA RESOLVER LAS AREAS SOMBREADAS

Answer 1

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Answer 2

AREA 1:

• A 1= 6cm(6cm)=36cm²
• A o= 3,1416 (3cm)² = 9πcm²
• 9πcm²/4= 2,25πcm² ( este es un cuarto de circulo )
• 3,1416 x 9= 28,2744cm²
• At= 36cm² - 28,2744cm² = 7,7256cm²
• 7,7256cm²

Area 2=

• A1= 8cm(8cm)=64cm²
• A2= $\pi$ (4cm²)= 3,1416(16cm²)=50,2656cm²

• AT ( area total)= 50,2656cm²-- 64cm²= 13,7344cm²

AREA 3 =

• NO  RESPUESTA

AREA 4:

• A1 : 18cm(18cm)=324cm²

• Ao: $\pi$ (9cm)= 3,1416 ( 81cm²)=254,4696cm²
• A(medio circulo)= 81$\pi$cm²/4= 20,25$\pi$cm²

• At= 324cm²- 254,4696cm²= 69,5304cm²

AREA 5 :

A1: 10cm(15cm)= 150cm²

A2: $\pi$ (2cm²)= 3,1416 (4cm²)= 12,5664cm²

At = 150cm²- 12,5664cm² = 137,4336cm²