Question

ayuda resolver las ecuaciones con racionales y comprueba la igualdad​

Answer 1

Respuesta:

$f)4x - \frac{2}{3} = \frac{6}{2} \\ 6(4x - \frac{2}{3} ) = 6 \times \frac{6}{2} \\ 24x - 4 = 18 \\ 24x = 18 + 4 \\ 24x = 22 \\ x = \frac{22}{24} = \frac{11}{12}$

$g)2x - \frac{1}{3} = \frac{2}{3} x + 2 \\ 3(2x - \frac{1}{3} ) = 3( \frac{2}{3}x + 2 ) \\ 6x - 1 = 2x + 6 \\ 6x - 2x = 6 + 1 \\ 4x = 7 \\ x = \frac{7}{4}$

$h) \frac{3}{2} x + 5 = 3 \\ 2( \frac{3}{2} x + 5) = 3 \times 2 \\ 3x + 10 = 6 \\ 3x = 6 - 10 \\ 3x = - 4 \\ x = - \frac{4}{3}$

$i) \frac{1}{5} - \frac{3}{2} x + \frac{2}{3} = \frac{10}{3} \\ 30( \frac{1}{5} - \frac{3}{2} x + \frac{2}{3} ) = 30 \times \frac{10}{3} \\ 6 - 45x + 20 = 100 \\ 26 - 45x = 100 \\ 26 - 100 = 45x \\ - 74 = 45x \\ - \frac{74}{45} = x$

$j)x - \frac{2}{5} = 2 \\ 5(x - \frac{2}{5} ) = 5 \times 2 \\ 5x - 2 = 10 \\ 5x = 10 + 2 \\ 5x = 12 \\ x = \frac{12}{5}$