Question

AYUDA PORFAVOR!!!!!! Resolver las siguientes ecuaciones empleando el método enseñado:
2x – 7 = -3

3x + 5 = -1

2x – 8 = 10

5x – 7 + 2x = 4x + 5

5x – 2x – 4 = x + 7 – 5

X – (2x + 1) = 8 – (3x + 3)

2(x – 1) – 5 = 14 – x

15x – 10 = 6x – (x – 2) + (-x + 3)

X + 3(x – 1) = 6 – 4 (2x + 3)

6 – 3(x+1) = -4x + 2(1 – x)

Answer 1

$2x - 7 = - 3 \\ 2x = - 3 + 7 \\ 2x = 4 \\ x = 2$

$3x + 5 = - 1 \\ 3x = - 1 - 5 \\ 3x = - 6 \\ x = - 2$

$2x - 8 = 10 \\ 2x = 10 + 8 \\ 2x = 18 \\ x = 9$

$5x - 7 + 2x = 4x + 5 \\ 7x - 7 = 4x + 5 \\ 7x - 4x = 5 + 7 \\ 3x = 12 \\ x = 4$

$5x - 2x - 4 = x + 7 - 5 \\ 3x - 4 = x + 2 \\ 3x - x = 2 + 4 \\ 2x = 6 \\ x = 3$

$x - (2x + 1) = 8 - (3x + 3) \\ x - 2x - 1 = 8 - 3x - 3 \\ - x - 1 = 5 - 3x \\ - x + 3x = 5 + 1 \\ 2x = 6 \\ x = 3$

$2(x - 1) - 5 = 14 - x \\ 2x - 2 - 5 = 14 - x \\ 2x - 7 = 14 - x \\ 2x + x = 14 + 7 \\ 3x =2 1 \\ x = 7$

$15x - 10 = 6x - (x - 2) + ( - x + 3) \\ 15x - 10 = 6x - x + 2 - x + 3 \\ 15x - 10 = 4x + 5 \\ 15x - 4x = 5 + 10 \\ 11x = 15 \\ x = \frac{15}{11}$

$x +3 (x - 1) = 6 - 4(2x + 3) \\ x + 3x - 3 = 6 - 8x - 12 \\ 4x - 3 = - 6 - 8x \\ 4x + 8x = - 6 + 3 \\ 12x = - 3 \\ x = - \frac{3}{12} \\ x = - \frac{1}{4}$

$6 - 3(x + 1) = - 4x + 2(1 - x) \\ 6 - 3x - 3 = - 4x + 2 - 2x \\ 3 - 3x = - 6x + 2\\ - 3x + 6x = 2 - 3 \\ 3x = - 1 \\ x = - \frac{1}{3}$

Answer 2

no me se la respuesta jajajajajajaja