Question

ayuda porfavor quimicos

Answer 1

m alcohol = 250 g

 m yodo = 2 g

 a)  % m/m = m soluto   x  100

                    `````````````

                      m solc.

preparar la m solución = masa soluto + masa solvente

 m solc. = 2 g + 250 g = 252 g

%m/m = 2 g  x  100

             ``````

             252 g

% m/m = 0.79 %

b) m yodo sólido = 0.5 g

m solución =  0.5 g   x   100

                     ``````````

                     0.79 g/g

m solución = 63.29 g

c) m solución = 50 g

m soluto = 0.79 g/g  x  50 g

                 `````````````````````````

                           100

m soluto = 0.395 g de yodo