ayuda porfavor
:) es de química
Respuestas a la pregunta
Respuesta:
1. F.M.: C6H12 2. F.M.: C18H36O18 3. F.M.: C4H8
4. F.M.: NaOH
Explicación:
1. carbono = 85.7 % H = 14.2 %
PM = 84 g/mol
a. calcular moles ( n = m/Mm)
n C = 85.7 g/ 12 g/mol = 7.14 mol
n H = 14.2 g / 1 g/mol = 14.2 mol
b. dividir cada resultado entre el menor de ellos
C: 7.14 mol / 7.14 mol = 1
H: 14.2 mol / 7.14 mol = 2
c. F.E.: CH2
d. Calcular Mm de la FE
C: 1 x 12 = 12 g/mol
H: 2 x 1 = 2 g/mol
Mm = 14 g/mol
e. calcular n
n = Mm FM / Mm FE
n = 84 g/mol
14 g/mol
n = 6
f. F.M.: (CH2)6 = C6H12
2. Carbono = 40 % H = 6.66 % O = 53.33 %
PM = 540 g/mol
a. calcular moles ( n = m/Mm)
n C = 40 g/ 12 g/mol = 3.33 mol
n H = 6.66 g / 1 g/mol = 6.66 mol
n O = 53.33 g / 16 g/mol = 3.33 mol
b. dividir cada resultado entre el menor de ellos
C: 3.33 mol / 3.33 mol = 1
H: 6.66 mol / 3.33 mol = 2
O: 3.33 mol / 3.33 mol = 1
c. F.E.: CH2O
d. Calcular Mm de la FE
C: 1 x 12 = 12 g/mol
H: 2 x 1 = 2 g/mol
O: 1 x 16 = 16 g/mol
Mm = 30 g/mol
e. calcular n
n = Mm FM / Mm FE
n = 540 g/mol
30 g/mol
n = 18
f. F.M.: (CH2O)18 = C18H36O18
3. Carbono = 85.7 % H = 14.2 %
PM = 56 g/mol
a. calcular moles ( n = m/Mm)
n C = 85.7 g/ 12 g/mol = 7.14 mol
n H = 14.2 g / 1 g/mol = 14.2 mol
b. dividir cada resultado entre el menor de ellos
C: 7.14 mol / 7.14 mol = 1
H: 14.2 mol / 7.14 mol = 2
c. F.E.: CH2
d. Calcular Mm de la FE
C: 1 x 12 = 12 g/mol
H: 2 x 1 = 2 g/mol
Mm = 14 g/mol
e. calcular n
n = Mm FM / Mm FE
n = 56 g/mol
14 g/mol
n = 4
f. F.M.: (CH2)4 = C4H8
4. Na = 57.5 % H = 2.5 % y O = 40 %
PM = 40 g/mol
a. calcular moles ( n = m/Mm)
n Na = 57.5 g / 23 g/mol = 2.5 mol
n H = 2.5g / 1 g/mol = 2.5 mol
n O = 40 g / 16 g/mol = 2.5 mol
b. dividir cada resultado entre el menor de ellos
Na: 2.5 mol / 2.5 mol = 1
H: 2.5 mol / 2.5 mol = 1
O: 2.5 mol / 2.5 mol = 1
c. F.E.: NaOH
d. Calcular Mm de la FE
Na: 1 x 23 = 23 g/mol
H: 1 x 1 = 1 g/mol
O: 1 x 16 = 16 g/mol
Mm = 40 g/mol
e. calcular n
n = Mm FM / Mm FE
n = 40 g/mol
40 g/mol
n = 1
f. F.M.: (NaOH)1 = NaOH