Question

Ayuda porfavor :(
doy corona​

Answer 1

Respuesta:

Explicación paso a paso:

1)

$a)7\sqrt{245}+2\sqrt{845}-9\sqrt{50}\\\\49\sqrt{5}+26\sqrt{5}-45\sqrt{2}\\\\75\sqrt{5}-45\sqrt{2}$

$b)3\sqrt{208}-5\sqrt{468}+\sqrt{52}\\\\12\sqrt{13}-30\sqrt{13}+2\sqrt{13}\\\\-16\sqrt{13}$

2)

$c)\sqrt[5]{3}\sqrt[6]{1}\\\\\sqrt[5]{3}\times \:1\\\\\sqrt[5]{3}$

$d)\sqrt[6]{4}\sqrt{11}\\\\\sqrt[3]{2}\sqrt{11}$

3)

$e)\frac{5}{\sqrt[4]{3^3}}\\\\\frac{5}{\sqrt[4]{27}}\\\\\frac{5\sqrt[4]{3}}{3}$

$f)\frac{2+\sqrt{11}}{\sqrt{7}}\\\\\frac{\left(2+\sqrt{11}\right)\sqrt{7}}{\sqrt{7}\sqrt{7}}\\\\\frac{\sqrt{7}\left(2+\sqrt{11}\right)}{7}$

$g)\frac{5+\sqrt{12}}{3+\sqrt{5}}\\\\\frac{5+2\sqrt{3}}{3+\sqrt{5}}\\\\\frac{\left(5+2\sqrt{3}\right)\left(3-\sqrt{5}\right)}{\left(3+\sqrt{5}\right)\left(3-\sqrt{5}\right)}\\\\\frac{15-5\sqrt{5}+6\sqrt{3}-2\sqrt{15}}{4}$