Question

ayuda porfabor y te doy coronita

Answer 1

Explicación paso a paso:

$3^8 * 3^4 * 3^1 = 3^{8+4+1} = 3^{13}\\5^x * 5^y = 5^{x+y} = 5^{x+y} \\6^8 * 6^m = 6^{8+m} = 6^{8+m} \\a * a^2 * a^3 = a^{1+2+3} = a^{6}$

Cocientes:

$9^7:9^5 = 9^{7-5} = 9^2\\3^4 :3^1 = 3^{4-1} = 3^3\\12^8 : 12^4 = 12^{8-4} = 12^4\\5^9 : 5^6 = 5^{9-6} = 5^3$