Question

ayuda por favor
x²-5x=5

x²- 16 =0

2x²-18=0

3x²-11=0

x²-49=0

-x²-x=0​

Answer 1

Respuesta:

25 creo es esas múltiples

Answer 2

Respuesta:

Explicación paso a paso:

• $x^{2} -5x=5$

$x^2-5x=5\\x^2-5x-5=0\\x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:1\cdot \left(-5\right)}}{2\cdot \:1}\\x_1=\frac{-\left(-5\right)+3\sqrt{5}}{2\cdot \:1},\:x_2=\frac{-\left(-5\right)-3\sqrt{5}}{2\cdot \:1}$

• $x^{2} - 16 =0$

$x^{2}=16\\x=\sqrt{16} \\x_1=4 ,x_2=-4$

• $2x^{2} -18=0$

$2x^{2} -18=0\\2x^{2} =18\\x^{2} =\frac{18}{2}\\x=\sqrt{9}\\x=3\\x_1=3 ,x_2=-3$

• $3x^{2} -11=0$

$3x^{2} -11=0\\3x^{2} =11\\x^{2} =\frac{11}{3} \\x=\sqrt{\frac{11}{3} } \\x_1=\sqrt{\frac{11}{3} } ,x_2=-\sqrt{\frac{11}{3} }$

• $x^{2} -49=0$

$x^{2} -49=0\\x^{2} =49\\x=\sqrt{49} \\x=7\\x_1=7,x_2=-7$

• $-x^{2} -x=0$

$-x^{2} -x=0\\x_{1,\:2}=\frac{-\left(-1\right)\pm \sqrt{\left(-1\right)^2-4\left(-1\right)\cdot \:0}}{2\left(-1\right)}\\x_{1,\:2}=\frac{-\left(-1\right)\pm \:1}{2\left(-1\right)}\\x_{1,\:2}=\frac{-\left(-1\right)\pm \:1}{2\left(-1\right)}$

$x_2=\frac{-\left(-1\right)+1}{2\left(-1\right)}=-1\\x_1=\frac{-\left(-1\right)-1}{2\left(-1\right)}=0$

Espero te ayude ;3