Question

AYUDA POR FAVOR
Representa por medio de una sola potencia el resultado de las siguientes expresiones:

9^10 / 9^9 =
〖16〗^5 / 〖16〗^2 =
3^15 / 〖13〗^7 =
〖11〗^11 / 〖11〗^4 =
〖14〗^18 / 〖14〗^8 =
〖27〗^9 / 〖27〗^9 =
2^(1/3) / 2^(1/8) =
4^(3/5) / 4^(1/4) =
〖10〗^(1/2) / 〖10〗^(1/4) =
r^5 / r^3 =
m^10 / m^8 =
d^45 / d^18 =
l^41 / l^20 =
y^50 / y^40 =
p^21 / p^19 =
h^(1/2) / h^(1/8) =
x^(5/4) / x^(1/4) =
h^(4/4) / 〖10〗^(1/4) =

Answer 1

Respuesta:

Espero haberte ayudado.

Explicación paso a paso:

•Aplicaremos resta de potencias, ya que tienen igual base.

a^4 / a^2 = 4 - 2 = 2

•: a^2

9^10 / 9^9 = 9

〖16〗^5 / 〖16〗^2 = 16^ 3

3^15 / 〖3〗^7 = 3^8

〖11〗^11 / 〖11〗^4 = 11^7

〖14〗^18 / 〖14〗^8 = 14^10

〖27〗^9 / 〖27〗^9 = 27

2^(1/3) / 2^(1/8) = 2^(5/24)

4^(3/5) / 4^(1/4) = 4^(7/20)

〖10〗^(1/2) / 〖10〗^(1/4) = 10^(1/4)

r^5 / r^3 = r^2

m^10 / m^8 = m^2

d^45 / d^18 = d^27

l^41 / l^20 = l^21

y^50 / y^40 = y^10

p^21 / p^19 = p^2

h^(1/2) / h^(1/8) = h^(6/16)

x^(5/4) / x^(1/4) = x