ayuda por favor, no entiendo bien estas operaciones.
Respuestas a la pregunta
Explicación paso a paso:
Tengamos primero claro que:
sen(30) = 1/2
cos(30) = √3/2
tan(30) = √3/3
sec(30)=1/cos(30)= 2√3/3
sen(45) = √2/2
cos(45) = √2/2
tan(45) = 1
sec(45) = 1/cos(45) = √2
sen(60) = √3/2
cos(60)= 1/2
tan(60) = √3
Luego:
A) 1/cos(30)+1/tan(60)-1/sen(45) = 1/(√3/2)+1/(√3)-1/(√2/2) = √3-√2
B) (sen(60)-cos²(45))/cos(60) = (1/2-(√2/2)²)/(1/2) = 0
C) (2sen(30)*cos(30))/(cos(60)+sec(30)) = (2*1/2*√3/2)/(1/2+2√3/3) ≈ 0,52
D) (sen²(30)+cos²(30)+1)/(sec(45)*tan(30)) = ((1/2)²+(√3/2)²+1)/(√2*√3/3) = √6
Explicación paso a paso:sen(30) = 1/2
cos(30) = √3/2
tan(30) = √3/3
sec(30)=1/cos(30)= 2√3/3
sen(45) = √2/2
cos(45) = √2/2
tan(45) = 1
sec(45) = 1/cos(45) = √2
sen(60) = √3/2
cos(60)= 1/2
tan(60) = √3
Luego:
A) 1/cos(30)+1/tan(60)-1/sen(45) = 1/(√3/2)+1/(√3)-1/(√2/2) = √3-√2
B) (sen(60)-cos²(45))/cos(60) = (1/2-(√2/2)²)/(1/2) = 0
C) (2sen(30)*cos(30))/(cos(60)+sec(30)) = (2*1/2*√3/2)/(1/2+2√3/3) ≈ 0,52
D) (sen²(30)+cos²(30)+1)/(sec(45)*tan(30)) = ((1/2)²+(√3/2)²+1)/(√2*√3/3) = √6