Question

AYUDA por favor me harían un gran favor, gracias​

Answer 1

Respuesta:

$a) \frac{2}{5} + \frac{2}{5} \times \frac{3}{6} = \frac{2}{5} + \frac{2}{5} \times \frac{1}{2} = \frac{2}{5} + \frac{1}{5} = \frac{3}{5}$

$b) \frac{16}{3} \times \frac{3}{7} - 2 \times \frac{3}{7} \div \frac{4}{7} = \frac{16}{3} \times \frac{3}{7} - 2 \times \frac{3}{7} \times \frac{7}{4} = \frac{16}{7} - \frac{3}{2} = \frac{32}{14} - \frac{21}{14} = \frac{11}{14}$

$c) \frac{7}{5} - \frac{3}{2} \times \frac{1}{25} - \frac{1}{5} = \frac{7}{5} - \frac{3}{50} - \frac{1}{5} = \frac{70}{50} - \frac{3}{50} - \frac{10}{5} = \frac{57}{50}$

$d) \frac{6}{3} \div \frac{2}{3} + \frac{5}{2} \times \frac{3}{2} = \frac{6}{3} \times \frac{3}{2} + \frac{5}{2} \times \frac{3}{2} = 3 + \frac{15}{4} = \frac{12}{4} + \frac{15}{4} = \frac{27}{4}$

$e) \frac{5}{2} \div \frac{3}{9} - \frac{4}{5} \times \frac{1}{6} - 6 = \frac{5}{2} \times \frac{9}{3} - \frac{4}{5} \times \frac{1}{6} - 6 = \frac{15}{2} - \frac{2}{15} - 6 = \frac{225}{30} - \frac{4}{30} - \frac{180}{30} = \frac{41}{30}$

$f) \frac{5}{2} \times ( \frac{2}{3} - \frac{4}{5} \times \frac{1}{6} ) = \frac{5}{2} \times ( \frac{2}{3} - \frac{2}{15} ) = \frac{5}{2} \times ( \frac{10}{15} - \frac{2}{15} ) = \frac{5}{2} \times \frac{8}{15} = \frac{4}{3}$

$g) \frac{1}{5} \div ( \frac{11}{3} - 1 ) = \frac{1}{5} \div ( \frac{11}{3} - \frac{3}{3} ) = \frac{1}{5} \div \frac{8}{3} = \frac{1}{5} \times \frac{3}{8} = \frac{3} {40}$

$h)(5 - 2 \times \frac{1}{4} ) - ( \frac{5}{3} + \frac{1}{6} ) = (5 - \frac{1}{2} ) - ( \frac{5}{3} + \frac{1}{6} ) = ( \frac{10}{2} - \frac{1}{2} ) - ( \frac{10}{6} + \frac{1}{6} ) = \frac{9}{2} - \frac{11}{6} = \frac{54}{12} - \frac{22}{12} = \frac{32}{12} = \frac{8}{3}$

$i)( \frac{1}{2} + \frac{5}{3} ) + 2 \div ( \frac{5}{2} + 3 \times \frac{2}{4} ) = ( \frac{1}{2} + \frac{5}{3} ) + 2 \div ( \frac{5}{2} + \frac{3}{2} ) = ( \frac{1}{2} + \frac{5}{3} ) + 2 \div \frac{8}{2} = ( \frac{3}{6} + \frac{10}{6} ) + 2 \times \frac{2}{8} = \frac{13}{6} + \frac{1}{2} = \frac{13}{6} + \frac{3}{6} = \frac{16}{6} = \frac{8}{3}$

$j) \frac{4}{3} - ( \frac{3}{2} - \frac{2}{3} \div \frac{3}{5} ) + \frac{1}{3} = \frac{4}{3} - ( \frac{3}{2} - \frac{2}{3} \times \frac{5}{3} ) + \frac{1}{3} = \frac{4}{3} - ( \frac{3}{2} - \frac{10}{9} ) + \frac{1}{3} = \frac{4}{3} - ( \frac{27}{18} - \frac{20}{18} ) + \frac{1}{3} = \frac{4}{3} - \frac{7}{18} + \frac{1}{3} = \frac{24}{18} - \frac{7}{18} + \frac{6}{18} = \frac{23}{18}$

$k)(1 - \frac{2}{5} \times \frac{3}{4} ) \div ( \frac{5}{3} + \frac{1}{6} ) = (1 - \frac{3}{10} ) \div ( \frac{5}{3} + \frac{1}{6} ) = ( \frac{10}{10} - \frac{3}{10} ) \div ( \frac{10}{6} + \frac{1}{6} ) = \frac{7}{10} \div \frac{11}{6} = \frac{7}{10} \times \frac{6}{11} = \frac{21}{55}$

$l)8 - 3 \times (5 - 3 \div \frac{2}{3} ) = 8 - 3 \times (5 - 3 \times \frac{3}{2} ) = 8 - 3 \times (5 - \frac{9}{2} ) = 8 - 3 \times ( \frac{10}{2} - \frac{9}{2} ) = 8 - 3 \times \frac{1}{2} = 8 - \frac{3}{2} = \frac{16}{2} - \frac{3}{2} = \frac{13}{2}$