[Ayuda por favor] Halla el valor de x, luego el valor de los tres ángulos en cada situación.
Respuestas a la pregunta
(Los ángulos del triangulo suman 180°)
Figura 1 :
4x + 4x + x = 180
9x = 180
x = 180/9
x = 20
.
a = 20
b = 4(20) = 80
c = 4(20) = 80
Figura 2 :
(La figura muestra un ángulo de 90°)
3x + 90 + 2x-15 = 180
5x + 75 = 180
5x = 180 - 75
5x = 105
.
x = 105/5
x = 21
a = 3(21) = 63
b = 90
c = 2(21)-15 = 42 - 15 = 27
Figura 3 :
(La figura muestra un ángulo de 90°)
2x+25 + 3x-5 + 90 = 180
5x + 110 = 180
5x = 180 - 110
5x = 70
x = 70/5
x = 14
c = 2(14)+25 = 28 + 25 = 53
d = 3(14)-5 = 42 - 5 = 37
e = 90
Figura 4 :
3x + 5x-14 + 2x+22 = 180
10x + 8 = 180
10x = 180 - 8
10x = 172
x = 172/10
x = 17.2
c = 3(17.2) = 51.6
d = 5(17.2)-14 = 72
e = 2(17.2)+22 = 56.4
Figura 5 :
2x + 6x-25 + 3x+18 = 180
11x - 7 = 180
11x = 180 + 7
11x = 187
x = 187/11
x = 17
m = 2(17) = 34
n = 6(17)-25 = 102 - 25 = 77
o = 3(17)+18 = 51 + 18 = 69
Figura 6 :
3x+24 + x-5 + 8x-40 = 180
12x - 21 = 180
12x = 180 + 21
12x = 201
x = 201/12
x = 16.75
m = 3(16.75)+24 = 74.25
n = (16.75)-5 = 11.75
o = 8(16.75)-40 = 134 - 40 = 94
Saludos!