Question

ayuda por favor doy corona :D

Answer 1

$por \: pitagoras \\ { (\sqrt{5} )}^{2} = {2}^{2} + {n}^{2} \\ 5 = 4 + {n}^{2} \\ 5 - 4 = {n}^{2} \\ 1 = {n}^{2} \\ 1 = n$