Question

Ayuda por favor doy corona
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Answer 1

Respuesta:

limx--->3 [4x-5/5x-1] = [4(3)-5/5(3)-1] = [12-5/15-1] = 7/14 = 1/2

$lim_{x - - - >5 }(3x - 7) = (3(5) - 7) = 15 - 7 = 8$

$lim_{x - - > 1}( \frac{x ^{2} + 4x + 2}{x + 2} ) = \frac{ {1}^{2} + 4 + 2 }{1 + 2} = \frac{7}{3}$