Question

Ayuda por favor de verdad la necesito :(​​

Answer 1

Respuesta:

$x + y = 4 \\ (x + y)^{2} = (4)^{2} \\ {x}^{2} + 2xy + {y}^{2} = 16 \\ {x}^{2} + {y }^{2} + 2xy = 16 \\ {x}^{2} + {y}^{2} + 2(5) = 16\\ {x}^{2} + {y}^{2} + 10 = 16 \\ {x}^{2} + {y}^{2} = 16 - 10 \\ {x}^{2} + {y}^{2} = 6 \\ \\ \\ \\ m = {x}^{2} + {y}^{2} \\ m = 6$

Explicación paso a paso:

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