Matemáticas, pregunta formulada por andrea212233, hace 6 meses

ayuda plis con el punto 4

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andrea212233: ayudenmennnnnnnnnnnnnnnnnnn

Respuestas a la pregunta

Contestado por MaqueraRivasLuisArtu
0

Hola!

Explicación paso a paso:

) Solución:

a)

( {14}^{2}  \times  {14}^{3} ) \div 14 \\  \\  =  \frac{( {14}^{2} \times  {14}^{3})  }{ {14}^{1} }  =  \frac{ {14}^{2 + 3} }{ {14}^{1} }   \\ =  \frac{ {14}^{5} }{ {14}^{1} }  =  {14}^{5 - 1}  =  {14}^{4}  = 38 \: 416

b)

 {8}^{4}  \times  {8}^{2}  =  {8}^{4 + 2}  =  {8}^{6}  = 262 \: 144

c)

 {2}^{8}  \times  {2}^{2}  \times 2  =  {2}^{8}  \times  {2}^{2}  \times  {2}^{1}  \\  =  {2}^{8 + 2 + 1}  =  {2}^{11}  = 2 \: 048

d)

 {5}^{3}  \times  {5}^{12}   \div  {5}^{9}  =  \frac{ {5}^{3} \times  {5}^{12}  }{ {5}^{9} }  =  \frac{ {5}^{3 + 12} }{ {5}^{9} }   \\  =  \frac{ {5}^{15} }{ {5}^{9} }  =  {5}^{15 - 9}  =  {5}^{6}  = 15 \: 625

e)

( {7}^{15}   \div {7}^{13} ) \div  {7}^{2}  = ( \frac{ {7}^{15} }{ {7}^{13} } ) \div  {7}^{2}  \\  =  ({7}^{15 - 13} ) \div  {7}^{2}  = ( {7}^{2} ) \div  {7}^{2}  =  \frac{ {7}^{2} }{ {7}^{2} }  =  {7}^{2 - 2}  =  {7}^{0}  = 1

f)

 { ({3}^{4} )}^{2}  \times 3 \div  {3}^{5}  =  {3}^{4 \times 2}  \times 3 \div  {3}^{5}   \\  =  {3}^{8}  \times  {3}^{1}  \div  {3}^{5}  =  {3}^{8 + 1}  \div  {3}^{5}  =  {3}^{9}  \div  {3}^{5}  \\  =  \frac{ {3}^{9} }{ {3}^{5} } =   {3}^{9 - 5}  =  {3}^{4}  = 81

G)

 {(3 \times 6)}^{8}  \div  {3}^{5}  =  {(3 \times 3 \times 2)}^{8}  \div  {3}^{5}  \\  =   {( {3}^{2}  \times 2)}^{8}  \div  {3}^{5}   =  {3}^{2 \times 8}  \times  {2}^{1  \times 8}  \div  {3}^{5}  \\  =  {3}^{16}  \times  {2}^{8}  \div  {3}^{5}  =  \frac{  {3}^{16}  \times  {2}^{8}  }{ {3}^{5} }  =  {3}^{16 - 5}  \times  {2}^{8}   \\ =  {3}^{11}  \times  {2}^{8}  =  177 \: 147 \times 256 =  \: 45  \: 349 \: 632

h)

 {( {9}^{7} )}^{0}  \times 9 = 1 \times 9 = 9

I)

 \frac{ {( {11}^{5} )}^{4}  \times  {( {11}^{3}) }^{6} }{ {11}^{11} }  =  \frac{ {11}^{5 \times 4}  \times  {11}^{3 \times 6} }{ {11}^{11} }  =  \frac{ {11}^{20}  \times  {11}^{18} }{ {11}^{11} }  \\  =  \frac{ {11}^{20 + 18} }{ {11}^{11} }  =  \frac{ {11}^{38} }{ {11}^{11} }  =  {11}^{38 - 11}  =  {11}^{27}

j)

  \frac{{( {13}^{6}) }^{2}  \times  { ({ ({13}^{3} )}^{4}) }^{2} }{ {13}^{10} } =  \frac{ {13}^{6 \times 2}  \times  {13}^{3 \times 4 \times 2} }{ {13}^{10} }  \\  =  \frac{ {13}^{12} \times  {13}^{24}  }{ {13}^{10} }  =  \frac{ {13}^{12 + 24} }{ {13}^{10} }  =  \frac{ {13}^{36} }{ {13}^{10} }  =  {13}^{36 - 10}  =  {13}^{26}  \\

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