Matemáticas, pregunta formulada por Jaivane4406, hace 1 año

Ayuda para resolver este problema:

(-6/5-2(9/2+5/15)*[3/4+(9/7-3/4)])/(-(3/20-3/30)÷[4/3 (9/8+8/9)]-(3/4-9/12) )=

Respuestas a la pregunta

Contestado por JuanCarlosAguero
1

Respuesta:

\frac{15 \: 370}{21}

Explicación paso a paso:

Resolución:

  \frac{ (- \frac{6}{5} -2(\frac{9}{2} + \frac{5}{15} ) \times [ \frac{3}{4} +( \frac{9}{7} - \frac{3}{4} )])}{(-( \frac{3}{20} - \frac{3}{30} )÷[ \frac{4}{3}  ( \frac{9}{8} + \frac{8}{9} )]-( \frac{3}{4} - \frac{9}{12} ) )}

\frac{ (- \frac{6}{5} -2(\frac{9}{2} + \frac{1}{3} ) \times [ \frac{3}{4} +( \frac{9}{7} - \frac{3}{4} )])}{(-( \frac{3}{20} - \frac{1}{10} )÷[ \frac{4}{3}  ( \frac{9}{8} + \frac{8}{9} )]-( \frac{3}{4} - \frac{3}{4} ) )}

\frac{ (- \frac{6}{5} -2(\frac{27}{6} + \frac{2}{6} ) \times [ \frac{3}{4} +( \frac{36}{28} - \frac{21}{28} )])}{(-( \frac{3}{20} - \frac{2}{20} )÷[ \frac{4}{3}  ( \frac{81}{72} + \frac{64}{72} )])}

\frac{ (- \frac{6}{5} -2(\frac{27 + 2}{6}) \times [ \frac{3}{4} +( \frac{36 - 21}{28})])}{(-( \frac{3 - 2}{20})÷[ \frac{4}{3}  ( \frac{81 + 64}{72})])}

\frac{ (- \frac{6}{5} -2(\frac{29}{6}) \times [ \frac{3}{4} +( \frac{15}{28})])}{(-( \frac{1}{20})÷[ \frac{4}{3}  ( \frac{145}{72})])}

\frac{ (- \frac{6}{5} -\frac{58}{6} \times [ \frac{3}{4} + \frac{15}{28}])}{(- \frac{1}{20}÷[\frac{580}{216}])}

\frac{ (- \frac{6}{5} -\frac{58}{6} \times [ \frac{21}{28} + \frac{15}{28}])}{(- \frac{1}{20}÷\frac{580}{216})}

\frac{ (- \frac{6}{5} -\frac{58}{6} \times [ \frac{21 + 15}{28}])}{(- \frac{1}{20}÷\frac{580}{216})}

\frac{ (- \frac{6}{5} -\frac{58}{6} \times [ \frac{36}{28}])}{(- \frac{1}{20} \times \frac{216}{580})}

\frac{ (- \frac{6}{5} -\frac{58}{6} \times \frac{36}{28})}{(- \frac{216}{11600})}

\frac{ (- \frac{6}{5} -\frac{2088}{168})}{- \frac{216}{11600}}

\frac{ (- \frac{1008}{840} -\frac{10440}{840})}{- \frac{216}{11600}}

\frac{ (\frac{ - 1008 - 10440}{840})}{- \frac{216}{11600}}

\frac{ (\frac{ -11448}{840})}{- \frac{216}{11600}}

\frac{ \frac{ 11448}{840}}{ \frac{216}{11600}}

 \frac{(11448)(11600)}{(840)(216)}

 \frac{132 \: 796 \: 800}{181 \: 440}

 \frac{15 \: 370}{21}

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