Question

AYUDA NETA SE LOS AGRADEZCO MUCHISIIMOOO:(

Answer 1

Explicación paso a paso:

Formula de binomio al cubo:  

(a ± b)³ = a³ ± 3a²b + 3ab² ± b³

Resolvamos:

6.

(2y-1)³ = (2y)³ - 3(2y)²(1) + 3(2y)(1)² - (1)³

(2y-1)³ = 8y³-12y²+6y-1

7.

(-3y+8x)³ = (-3y)³ + 3(-3y)²(8x) + 3(-3y)(8x)² + (8x)³

(-3y+8x)³ = -27y³+216y²x-576yx²+512x³

8.

(3x⁴-6y⁴)³ = (3x⁴)³ - 3(3x⁴)²(6y⁴) + 3(3x⁴)(6y⁴)² - (6y⁴)³

(3x⁴-6y⁴)³ = 27x¹²-162x⁸y⁴+324x⁴y⁸-216y¹²

9.

(9x+2)³ = (9x)³ + 3(9x)²(2) + 3(9x)(2)² + (2)³

(9x+2)³ = 729x³+486x²+108x+8

Formula de binomio al  cuadrado:

(a ± b)² = a² ± 2ab + b²

Resolvamos:

10.

(5x+10y)² = (5x)² + 2(5x)(10y) + (10y)²

(5x+10y)² = 25x²+100xy+100y²

Answer 2

RESOLVER:

Antes que nada, te voy a dejar la plantilla que se usa en este tipo de operaciones:

Cuando está elevado al cuadrado:

$\bf{\left(a+b\right)^2=a^2+2ab+b^2}$

$\bf{\left(a-b\right)^2=a^2-2ab+b^2}$

Cuando está elevado al cubo:

$\bf{\left(a+b\right)^3=a^3+3a^2b+3ab^2+b^3}$

$\bf{\left(a-b\right)^3=a^3-3a^2b+3ab^2-b^3}$

Ahora que ya sabemos la fórmula, resolvemos:

a) $\left(2y-1\right)^3$

$\left(2y-1\right)^3=\left(2y\right)^3-3\left(2y\right)^2\cdot \:1+3\cdot \:2y\cdot \:1^2-1^3\\\\=\left(2y\right)^3-3\left(2y\right)^2\cdot \:1+3\cdot \:2y\cdot \:1^2-1^3\\\\\boxed{=8y^3-12y^2+6y-1}$

b) $\left(-3y+8x\right)^3$

$\left(-3y+8x\right)^3=\left(-3y\right)^3+3\left(-3y\right)^2\cdot \:8x+3\left(-3y\right)\left(8x\right)^2+\left(8x\right)^3\\\\=\left(-3y\right)^3+3\left(-3y\right)^2\cdot \:8x+3\left(-3y\right)\left(8x\right)^2+\left(8x\right)^3\\\\\boxed{=-27y^3+216y^2x-576yx^2+512x^3}$

c) $\left(3x^4-6y^4\right)^3$

$\left(3x^4-6y^4\right)^3=\left(3x^4\right)^3-3\left(3x^4\right)^2\cdot \:6y^4+3\cdot \:3x^4\left(6y^4\right)^2-\left(6y^4\right)^3\\\\=\left(3x^4\right)^3-3\left(3x^4\right)^2\cdot \:6y^4+3\cdot \:3x^4\left(6y^4\right)^2-\left(6y^4\right)^3\\\\\boxed{=27x^{12}-162x^8y^4+324x^4y^8-216y^{12}}$

d) $\left(9x+2\right)^3$

$\left(9x+2\right)^3=\left(9x\right)^3+3\left(9x\right)^2\cdot \:2+3\cdot \:9x\cdot \:2^2+2^3\\\\=\left(9x\right)^3+3\left(9x\right)^2\cdot \:2+3\cdot \:9x\cdot \:2^2+2^3\\\\\boxed{=729x^3+486x^2+108x+8}$

e) $\left(5x+10y\right)^2$

$\left(5x+10y\right)^2=\left(5x\right)^2+2\cdot \:5x\cdot \:10y+\left(10y\right)^2\\\\=\left(5x\right)^2+2\cdot \:5x\cdot \:10y+\left(10y\right)^2\\\\\boxed{=25x^2+100xy+100y^2}$

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