Ayuda necesito resolver estooop
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18- Mm CH4 = 16 g/mol
n(moles) = masa/Mm
n = 0.25
masa = 0.25 x 16 g/mol = 4 g
19. n = 0.125 moles
Mm Na2HPO4 = 142 g/mol
m = 0.125 moles x 142 g/mol = 17.75 g
20. Mm agua = 18 g/mol
m = 18 g/mol x 0.23 mol = 4.14 g
21. MmH2SO4 = 98 g/mol
m = 32.5 moles x 98 g/mol = 3185 g
22. Mm butano = 58 g/mol
m = 50 g
n = 50 g / 58 g/mol = 0.862 moles de butano
23. Mm H2CO3 = 62 g/mol
n = 62 g / 62 g/mol = 1 mol
24. Mm Na2SO4 = 142 g/mol
moles (n) = 142 g / 142 g/mol = 1 mol
25. Mm KHCO3 = 100 g/mol
n = 10 g / 100 g/mol = 0.1 mol
29. Mm NaOH = 40 g/mol
moles = 1 g / 40 g/mol = 0.025 moles de NaOH
31. Mm SO2 = 64 g/mol
g = 1 x 10²¹ moléculas x 64 g
``````````
6.022 x 10²³ moleculas
g = 0.106
33.
Mm H2O = 18 g/mol
g = 1 molécula x 18 g
````````````
6.022 x ²³ moléculas
g = 2.98 x ²³
34.
Mm O2 = 32 g/mol
g = 1 molecula de O2 x 32 g O2
``````````````````
6.022 x ²³ moleculas
g = 5.31 x 10⁻²³
35. Mm C12H22O11 = 342 g/mol
g = 1 molecula x 342 g
````````````````````
6.022 x 10²³ moléculas
g = 5.68 x 10⁻²²
37. Mm NaOH = 40 g/mol
particulas = 1 g x 6.022 x 10²³ particulas
``````````````````````````````````
39.99 g
particulas= 1.50 x 10 ²²
n(moles) = masa/Mm
n = 0.25
masa = 0.25 x 16 g/mol = 4 g
19. n = 0.125 moles
Mm Na2HPO4 = 142 g/mol
m = 0.125 moles x 142 g/mol = 17.75 g
20. Mm agua = 18 g/mol
m = 18 g/mol x 0.23 mol = 4.14 g
21. MmH2SO4 = 98 g/mol
m = 32.5 moles x 98 g/mol = 3185 g
22. Mm butano = 58 g/mol
m = 50 g
n = 50 g / 58 g/mol = 0.862 moles de butano
23. Mm H2CO3 = 62 g/mol
n = 62 g / 62 g/mol = 1 mol
24. Mm Na2SO4 = 142 g/mol
moles (n) = 142 g / 142 g/mol = 1 mol
25. Mm KHCO3 = 100 g/mol
n = 10 g / 100 g/mol = 0.1 mol
29. Mm NaOH = 40 g/mol
moles = 1 g / 40 g/mol = 0.025 moles de NaOH
31. Mm SO2 = 64 g/mol
g = 1 x 10²¹ moléculas x 64 g
``````````
6.022 x 10²³ moleculas
g = 0.106
33.
Mm H2O = 18 g/mol
g = 1 molécula x 18 g
````````````
6.022 x ²³ moléculas
g = 2.98 x ²³
34.
Mm O2 = 32 g/mol
g = 1 molecula de O2 x 32 g O2
``````````````````
6.022 x ²³ moleculas
g = 5.31 x 10⁻²³
35. Mm C12H22O11 = 342 g/mol
g = 1 molecula x 342 g
````````````````````
6.022 x 10²³ moléculas
g = 5.68 x 10⁻²²
37. Mm NaOH = 40 g/mol
particulas = 1 g x 6.022 x 10²³ particulas
``````````````````````````````````
39.99 g
particulas= 1.50 x 10 ²²
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