Question

Ayuda g(x)= x+1 / x^2-x-6

Answer 1

Respuesta:

g(x)= x+1 / x^2-x-6

gx−{(x⋅x2)+1x2−x−6}=0  

gx−{x3+1x2−x−6}=0

gx−{(x3+1)−(x⋅x2)x2−6}=0

gx−{1x2−6}=0

gx−{−6x2+1x2}=0

(gx⋅x2)−(−6x2+1)x2=0

gx3+6x2−1x2=0

x3g+6x2−1=0,x2≠0

(g)⋅x3+(6)⋅x2+(−1)=0