Question

ayuda
g) √28 + √7+ 35/√7
h) √98-√50+18/√2
i) √75-√12-3/√3​

Answer 1

$g) \sqrt{28} + \sqrt{7} + 35 \sqrt{7} = \\ \sqrt{ {2}^{2} \times 7 } + \sqrt{7} + 35 \sqrt{7} = \\ 2 \sqrt{7} + \sqrt{7} + 35 \sqrt{7} = \\ (2 + 1 + 35) \sqrt{7} = \\ 38 \sqrt{7}$

$h) \sqrt{98} - \sqrt{50} + 18 \sqrt{2} = \\ \sqrt{2 \times {7}^{2} } - \sqrt{2 \times {5}^{2} } + 18 \sqrt{2} = \\ 7 \sqrt{2} - 5 \sqrt{2} + 18 \sqrt{2} = \\ (7 - 5 + 18) \sqrt{2} = \\ 20 \sqrt{2}$

$i) \sqrt{75} - \sqrt{12} - 3 \sqrt{3} = \\ \sqrt{3 \times {5}^{2} } - \sqrt{ {2}^{2} \times 3 } - 3 \sqrt{3} = \\ 5 \sqrt{3} - 2 \sqrt{3} - 3\sqrt{3} = \\ (5 - 2 - 3) \sqrt{3} = \\ 0 \times \sqrt{3} = \\ 0$