Question

Ayuda doy corona porfavor​

Answer 1

Respuesta:

$1).\int(5 {x}^{4} + 3 {x}^{2} - 5x)dx = \int 5 {x}^{4}dx+ \int 3 {x}^{2}dx - \int5xdx \\ = {x}^{5} + {x}^{3} - \frac{5}{2} {x}^{2} + k$

$2).\int( \frac{10}{x} + 5 \sin(x) - 10 \cos(x) )dx = \int \frac{10}{x} dx+ \int 5 \sin(x)dx - \int10 \cos(x)dx \\ = \frac{ - 5}{ {x}^{2} } - 5 \cos(x) - 10 \sin(x) + k$