Question

ayuda doy corona con el procedimiento ​

Answer 1

Respuesta:

Perímetro $\approx$ 20.4696, distancia $\approx$ 11.0454

Explicación paso a paso:

Perímetro:

$P_{ABC} = D_{AB} + D_{BC} + D_{CA}\\\\D_{AB} = \sqrt{(-1-5)^2+(3-2)^2} = \sqrt{(-6)^2+(1)^2} = \sqrt{36+1} = \sqrt{37}\\D_{BC} = \sqrt{(1-(-1))^2+(9-3)^2} = \sqrt{(1+1)^2+(6)^2} = \sqrt{2^2+6^2} = \sqrt{4+36} = \sqrt{40} = 2\sqrt{10}\\D_{CA} = \sqrt{(5-1)^2+(2-9)^2} = \sqrt{(4)^2+(-7)^2} = \sqrt{16+49} = \sqrt{65}\\\\P_{ABC} = D_{AB} + D_{BC} + D_{CA}\\P_{ABC} = \sqrt{37} + 2\sqrt{10} + \sqrt{65} \approx 20.4696$

Distancia:

$D_{AB}=\sqrt{(-1-10)^2+(3-2)^2}=\sqrt{(-11)^2+(1)^2}=\sqrt{121+1}=\sqrt{122}\approx11.0454$