Question

ayuda, doy corona
..... ​

Answer 1

Respuesta:

$\frac{ {x}^{8} \times {y}^{6} \times {x}^{9} \times {y}^{8} }{ {x}^{8} \times {y}^{15} \times {x}^{12} \times {y}^{4} } = {x}^{ - 3} {y}^{ - 5}$