Question

AYUDA dare corona
tema: series geometricas
calcula el valor de P:
8748+2916+972+......+4​

Answer 1

Respuesta:

      13120

Explicación paso a paso:

$Razon: r = \frac{2916}{8748} = \frac{1}{3}$

$a_{n} =a_{1} r^{n-1}$

$4 =8748 ( \frac{1}{3} )^{n-1}$

$\frac{4}{8748} ( \frac{1}{3} )^{n-1x^{2} }$

$\frac{1}{2187} =(\frac{1}{3} )^{n-1}$

$(\frac{1}{3} )^{7} = (\frac{1}{3} )^{n-1}$

7 = n -1

7 + 1 = n

n = 8

$P = \frac{a_{n} r - a_{1} }{r-1}$

$P{ =\frac{4(\frac{1}{3} )-8748}{\frac{1}{3}-1 } = \frac{\frac{-26240}{3} }{\frac{-2}{3} } =\frac{-26240}{-2} = 13120$

$P = 13120$

Answer 2

Respuesta:

no entiendo

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