Question

Ayuda con procedimiento doy coronita​

Answer 1

Respuesta:

$( { \frac{8}{10}) }^{2} - {( \frac{4}{10} )}^{2} + \sqrt{ { (\frac{7}{3}) }^{2} } \\ \frac{64}{100} - \frac{16}{100} + \frac{7}{3} \\ \frac{48}{100} + \frac{7}{3} = \frac{211}{75}$

$( \sqrt{ (\frac{64}{216}) } \times \sqrt{( \frac{64}{216}) } - \sqrt{ \frac{36}{100} } \\ \sqrt{( \frac{64}{216}) } ^{2} - \sqrt{ (\frac{6}{10} )}^{2} \\ \frac{8 \times 8}{27 \times 8} - \frac{3}{5} \\ \frac{8}{27} - \frac{3}{5} = - \frac{41}{135}$