Question

ayuda con la pregunta que dice calcula el valor numerico de los siguientes polinomios si
x= -2, y= -4 y z=4

Answer 1

x = -2
y = -4
z = 4

Simplemente reemplazamos.

1. 5x²y+3y²z-2xz

= 5(-2)² (-4) + 3(-4)²(4)-2(-2)(4)

= 5 (4)·(-4) + 3 (16)·(4) + 16

= -80 +192 +16

=128

2. 8-2xy²+3x²y-z²

= 8-2(-2)(-4)²+3(-2)²(-4)-(4)²

= 8-2(-2)·16+3·4(-4) - 16

= 8-(-64)·16 -48-16

= 8+64-48-16

= 8

3. 3/4x²y²-1/4xz²-13

= 3/4 (-2)²(-4)² -1/4(-2)(4)²-13

= 3/4 (-2)²(-4)² +1/4(2)(4)²-13

= 3/4 (4) (16) + 1/4 (2) (16)-13

= 48 + 8 - 13

= 43

4. -2/3 xy³z² + 1/9 x³y²z

= -2/3 (-2)·(-4)³·(4)²+1/9(-2)³(-4)²(4)

= -2/3 (-2)·(-64)·(16) + 1/9 (-8)·(16)·(4)

= -4096/3 - 512/9 

= -12800/9

¡Espero haberte ayudado, saludos!

Answer 2

Respuesta:

x = -2

y = -4

z = 4

Simplemente reemplazamos.

1. 5x²y+3y²z-2xz

= 5(-2)² (-4) + 3(-4)²(4)-2(-2)(4)

= 5 (4)·(-4) + 3 (16)·(4) + 16

= -80 +192 +16

=128

2. 8-2xy²+3x²y-z²

= 8-2(-2)(-4)²+3(-2)²(-4)-(4)²

= 8-2(-2)·16+3·4(-4) - 16

= 8-(-64)·16 -48-16

= 8+64-48-16

= 8

3. 3/4x²y²-1/4xz²-13

= 3/4 (-2)²(-4)² -1/4(-2)(4)²-13

= 3/4 (-2)²(-4)² +1/4(2)(4)²-13

= 3/4 (4) (16) + 1/4 (2) (16)-13

= 48 + 8 - 13

= 43

4. -2/3 xy³z² + 1/9 x³y²z

= -2/3 (-2)·(-4)³·(4)²+1/9(-2)³(-4)²(4)

= -2/3 (-2)·(-64)·(16) + 1/9 (-8)·(16)·(4)

= -4096/3 - 512/9  

= -12800/9

¡Espero haberte ayudado, saludos!

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